carlosp_uk
03-16-2003, 01:42 PM
Hello people!
I am developing an application for PocketPC/Smartphone.
When the app initialises, it needs to know the default location of the start menu. On the Smartphone this is \IPSM\Windows\Start Menu\
.....but what is it on a standard PocketPC?
Amd... I tried to find it via RAPI using CeGetSpecialFolderPath method, but it doesn't seem to work. If anyone has any concrete examples of using this function in VB, please please respond!
Here's my code:
Private Const CSIDL_STARTMENU = &HB
Dim nBufferLength As Long
Dim lpBuffer As String
If CeGetSpecialFolderPath(CSIDL_STARTMENU, nBufferLength, lpBuffer) > 0 Then
MsgBox “Start Menu Is “ & lpBuffer
End If
Help appreciated,
Carl
I am developing an application for PocketPC/Smartphone.
When the app initialises, it needs to know the default location of the start menu. On the Smartphone this is \IPSM\Windows\Start Menu\
.....but what is it on a standard PocketPC?
Amd... I tried to find it via RAPI using CeGetSpecialFolderPath method, but it doesn't seem to work. If anyone has any concrete examples of using this function in VB, please please respond!
Here's my code:
Private Const CSIDL_STARTMENU = &HB
Dim nBufferLength As Long
Dim lpBuffer As String
If CeGetSpecialFolderPath(CSIDL_STARTMENU, nBufferLength, lpBuffer) > 0 Then
MsgBox “Start Menu Is “ & lpBuffer
End If
Help appreciated,
Carl