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View Full Version : TeamCalendar now in BETA - View Co-Worker's Calendar and Plan Meeting from the Smartphone


Kris Kumar
04-04-2007, 04:30 PM
<div class='os_post_top_link'><a href='http://www.teamcalendar.com/' target='_blank'>http://www.teamcalendar.com/</a><br /><br /></div><i>"Smartphone &amp; Pocket PC users throughout the world can now bring their "virtual secretary" along while they are on the move. HandStep is launching an intuitive program that enables mobile co-workers to schedule meetings on the spot via their PDA or SmartPhone. ... TeamCalendar gives you a complete overview of your colleagues’ schedules directly from your PDA or Smartphone for any given day or week. What’s more, you can book meetings on the spot – so no more phone calls or emails trying to set up that all-important meeting."</i><br /><br /> <img src="http://www.smartphonethoughts.com/images/Kris-apr2007-teamcalendarhs.jpg" alt="User submitted image" title="User submitted image"/> <br /><br />If you are always away from your desktop and want to schedule meetings on the go, then TeamCalendar is the application to check out. It is currently in BETA, and expected to be released sometime in July. The price seems to be a bit steep for a feature that I would like my Windows Mobile device to provide out of the box. But sadly even the upcoming Windows Mobile 6 will not have support for this. Windows Mobile 6 will enable you to see the attendees and invite new ones, but you will not be able to see if they are available or not.

Jerry Raia
04-04-2007, 04:57 PM
Another stupid omission by Microsoft. :roll:

Mike Temporale
04-05-2007, 02:44 AM
Great idea - Expensive, but great.

VanHlebar
04-06-2007, 01:10 AM
Does anyone know why this feature isn't available as part of the OS? I could even understand if it was say some kind of add-on when you were using Exchange Server or something. I have been wanting something like this ever since I started using a PPC 6 years ago.

Know if I could just get my Exchange Server to connect to my home network, part of the equation would be solved for me. :lol:

-Eric